1+cos(8x)=2cos^2(4x)

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Solution for 1+cos(8x)=2cos^2(4x) equation:


Simplifying
1 + cos(8x) = 2cos2(4x)

Remove parenthesis around (8x)
1 + cos * 8x = 2cos2(4x)

Reorder the terms for easier multiplication:
1 + 8cos * x = 2cos2(4x)

Multiply cos * x
1 + 8cosx = 2cos2(4x)

Remove parenthesis around (4x)
1 + 8cosx = 2cos2 * 4x

Reorder the terms for easier multiplication:
1 + 8cosx = 2 * 4cos2 * x

Multiply 2 * 4
1 + 8cosx = 8cos2 * x

Multiply cos2 * x
1 + 8cosx = 8cos2x

Solving
1 + 8cosx = 8cos2x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8cos2x' to each side of the equation.
1 + 8cosx + -8cos2x = 8cos2x + -8cos2x

Combine like terms: 8cos2x + -8cos2x = 0
1 + 8cosx + -8cos2x = 0

Add '-1' to each side of the equation.
1 + 8cosx + -1 + -8cos2x = 0 + -1

Reorder the terms:
1 + -1 + 8cosx + -8cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 8cosx + -8cos2x = 0 + -1
8cosx + -8cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
8cosx + -8cos2x = -1

Reorder the terms:
1 + 8cosx + -8cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 8cosx + -8cos2x = 0

The solution to this equation could not be determined.

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